起线程已经重写run方法了,为啥还需要单独执行start方法才能运行?

1.通过我们在启动线程的时候使用的start,为什么不用run呢? 因为start()会新开一个线程来执行;而run只是一个普通想法,相当于当前线程来调用,不会启动新线程;
 
2.start()只能调用

本文最后更新时间:  2023-02-23 16:27:16

1.通过我们在启动线程的时候使用的start,为什么不用run呢? 因为start()会新开一个线程来执行;而run只是一个普通想法,相当于当前线程来调用,不会启动新线程;

 

2.start()只能调用一次,run()可以调用多次

start()与run()源码查看

1.先来看下start()的源码,start()启动线程其实是通过start0()启动的

public synchronized void start() {

/**

* This method is not invoked for the main method thread or \"system\"

* group threads created/set up by the VM. Any new functionality added

* to this method in the future may have to also be added to the VM.

*

* A zero status value corresponds to state \"NEW\".

*/

if (threadStatus != 0)

throw new IllegalThreadStateException();

/* Notify the group that this thread is about to be started

* so that it can be added to the group's list of threads

* and the group's unstarted count can be decremented. */

group.add(this); //添加到线程组

boolean started = false;

try {

start0(); //调用本地方法start0()来启动新的线程

started = true;

} finally {

try {

if (!started) {

group.threadStartFailed(this);

}

} catch (Throwable ignore) {

/* do nothing. If start0 threw a Throwable then

it will be passed up the call stack */

}

}

}

private native void start0(); //本地方法start0() 

2.run()源码

public void run() {

if (target != null) {

target.run();

}

}

只是调用了runnable里面的run方法,并没有创建新的线程

start()与run()测试

理论也看了,源码也看了,线程来实践一下是不是这样的

 

public class StartRun {

public static void main(String[] args){

Thread test=new Thread(new Runnable() {

@Override

public void run() {

System.out.println(Thread.currentThread().getName());

}

});

test.run();

}

}

对应的输出结果为main,即主线程,并没有创建新的线程

public class StartRun {

public static void main(String[] args){

Thread test=new Thread(new Runnable() {

@Override

public void run() {

System.out.println(Thread.currentThread().getName());

}

});

test.start();

}

对应的输出结果为Thread-0,创建了新的线程

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